A12荐读 - 多云转晴

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思路:倒序单调栈。弹出所有 ≤ 当前身高的元素(这些人都能被看到),count 为弹出数量;若栈非空,还能看到栈顶(第一个更高的人),故 +1。能看到的人数 = count + (栈非空 ? 1 : 0)。

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So I made a first tool to automate downloading this data.,推荐阅读体育直播获取更多信息

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